copy linked list with arbitrary pointer leetcode

18 Jul. Copy List with Random Pointer. 3) Now restore the original and copy linked lists in this fashion in a single loop. GitHub Gist: instantly share code, notes, and snippets. First we can create a new linked list without considering the Random pointer, which is straight forward: Scan every node in the original list and create the new list (line 21- 27 in the code below). Posted on July 18, 2014 January 21, 2020 Author Sheng 1. Return a deep copy of the list. Solution to Copy List with Random Pointer by LeetCode. [Leetcode] Copy List with Random Pointer A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Copy List with Random Pointer A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. This works because original->next is nothing but copy of original and Original->arbitrary-> next is nothing but copy of arbitrary. Analysis: This problem returns a new linked list, which has the same value and structure of the original one. Return a deep copy of the list. You keep the random pointers as they are for now. Copy List with Random Pointer. So while I was browsing LeetCode to practice some LinkedList problems I came across this wonderful problem 138. ... # Definition for singly-linked list with a random pointer. LeetCode 138. [LeetCode] Copy List with Random Pointer, Solution A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. You traverse the original linked list and create another linked list, whose nodes are the same as in the original list, with proper next pointers, pointing to the corresponding nodes of the new list.

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